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AD is a median of △ABC with vertices A(5, −6), B(6, 4) and C(0, 0). Length AD is equal to :
The distance of the point A(–3, –4) from x-axis is
Prove that abscissa of a point P which is equidistant from points with coordinates A(7, 1) and B(3, 5) is 2 more than its ordinate.
The distance of point (a, –b) from x-axis is
The distance of point P(3a, 4a) from y-axis is
Find a relation between x and y such that P(x, y) is equidistant from the points A(3, 5) and B(7, 1). Hence, write the coordinates of the points on x-axis and y-axis which are equidistant from points A and B.
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