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In a right triangle ABC, right-angled at A, if sin B = 1/4, then the value of sec B is
If a sec θ + b tan θ = m and b sec θ + a tan θ = n, prove that a² + n² = b² + m²
Use the identity : sin²A + cos²A = 1 to prove that tan²A + 1 = sec²A. Hence, find the value of tan A, when sec A = 5/3, where A is an acute angle.
Prove that : (cos θ – 2 cos³θ)/(sin θ – 2 sin³θ) + cot θ = 0.
Given that sin θ + cos θ = x, prove that sin⁴θ + cos⁴θ = (2 – (x² – 1)²)/2.
The value of (1 − 2 sin² 60°) is same as that of
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