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In the given figure, ABCD is a quadrilateral. Diagonal BD bisects ∠B and ∠D both. Prove that :
Given ΔABC ~ ΔPQR, ∠A = 30° and ∠Q = 90°. The value of (∠R + ∠B) is
Given △ABC ~ △PQR, ∠A = 30° and ∠Q = 90°. The value of (∠R + ∠B) is
AD and PS are angle bisectors of ∠A and ∠P of triangles ABC and PQR. If △ABC ~ △PQR, prove that △ACD ~ △PRS.
AD and PS are medians of triangles ABC and PQR respectively such that △ABD ~ △PQS. Prove that △ABC ~ △PQR.
△ABC and △PQR are shown in the adjoining figures. The measure of ∠C is :
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