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Find the values of A and B (0 ≤ A < 90°, 0 ≤ B < 90°), if tan (A + B) = 1 and tan (A – B) = 1/√3.
Prove that tan 45° = 1 geometrically.
If sin 3A = 1, then find the value of cos 2A – tan² 45°.
If (sec A + tan A) (1 – sin A) = k cos A, then find the value of k.
Evaluate : cos 45°/(tan 30° + sin 60°)
For A = 30° and B = 60°, verify that tan (B – A) = (tan B – tan A)/(1 + tan A tan B)
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