ABCD is a rectangle and P, Q, R and S are mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rhombus.

Congruence of Triangles, Rhombus as Special Parallelogram, Mid-point Theorem for Triangle | PadhAiPro

Question

TextCongruence of TrianglesRhombus as Special ParallelogramMid-point Theorem for Triangle

Similar Questions

Which of the following is not a criterion for congruence of triangles?

MCQ (Single)Congruence of TrianglesSAS Congruence Rule for TrianglesASA Congruence Rule for TrianglesSSS Congruence Rule for Triangles

If ABC is an isosceles triangle with AB=AC. BD and CE are two medians of the triangle. Prove that BD=CE.

TextCongruence of TrianglesIsosceles Triangle Property of Equal Angles

If measure of opposite angles of a parallelogram are (60 − x)° & (3x − 4)°, find the measures of angles of the parallelogram.

TextOpposite Angles of Parallelogram are EqualConditions for Quadrilateral to be ParallelogramMid-point Theorem for Triangle

Fill in the blanks:

CASE_STUDIESOpposite Angles of Parallelogram are EqualConditions for Quadrilateral to be ParallelogramMid-point Theorem for Triangle

M,N & P are the mid-points of sides AB, AC & BC of a △ ABC respectively. If MN= 3 cm, NP= 3.5 cm and MP= 2.5 cm, calculate BC, AB & AC respectively.

TextOpposite Angles of Parallelogram are EqualConditions for Quadrilateral to be ParallelogramMid-point Theorem for Triangle

Assertion (A): In △ABC, E and F are the midpoints of AC and AB respectively. The altitude AP at BC intersects FE at Q. Then, AQ = QP. Reason (R): Q is the midpoint of AP.

Assertion-ReasonMid-point Theorem for Triangle