In the given figure, AOB is the diameter of circle with centre O and P is any point on the circle. Find ∠APB.

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Perpendicular from Centre Bisects the Chord, Angle in Semicircle is Right Angle | PadhAiPro

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TextPerpendicular from Centre Bisects the ChordAngle in Semicircle is Right Angle

Two circles intersect at two points A and B. AD and AC are diameters to the two circles (see Fig. 9.21). Prove that B lies on the line segment DC.

If circles are drawn taking two sides of a triangle as diameters, prove that the point of intersection of these circles lie on the third side.

Two concentric circles are of radii 5 cm and 3 cm. Find the length of the chord of the larger circle which touches the smaller circle.

AD is a diameter of a circle and AB is a chord. If AD = 34 cm, AB = 30 cm, the distance of AB from the centre of the circle is :

In Fig. 10.3, if OA = 5 cm, AB = 8 cm and OD is perpendicular to AB, then CD is equal to:

In Fig.10.5, if AOB is a diameter of the circle and AC = BC, then ∠CAB is equal to: