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In Figure, is shown a sector OAP of a circle with centre O, containing ∠θ. AB is a perpendicular to the radius OA and meets OP produced at B. Prove that the perimeter of shaded region is r [tan θ + sec θ + πθ/180° – 1]
Assertion (A): sin θ = opposite side/hypotenuse Reason (R): tan 90° = 0
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