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Prove that abscissa of a point P which is equidistant from points with coordinates A(7, 1) and B(3, 5) is 2 more than its ordinate.
The coordinates of the end points of the line segment AB are A(−2, −2) and B(2, −4). P is the point on AB such that BP = 4/7 AB. Find the coordinates of point P.
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