In the given figure, DE || AC and BE/EC = BC/CP. Prove that DC || AP.

Question

TextConverse of Basic Proportionality TheoremCBSE PYQ

Page 1 of 1

Similar Questions

State the converse of "Basic Proportionality Theorem" and use it to prove the following : Line segment joining mid-points of any two sides of a triangle is parallel to the third side.

TextConverse of Basic Proportionality Theorem

In a △ ABC, P and Q are points on AB and AC respectively such that PQ || BC. Prove that the median AD, drawn from A to BC, bisects PQ.

TextBasic Proportionality Theorem (Thales Theorem)

Converse of Basic Proportionality Theorem

ASSERTION (A): Line joining the midpoints of two sides of triangle is parallel to the third side. REASON (R): If a line divides two sides of a triangle in the same ratio then it is parallel to the third side.

Assertion-ReasonConverse of Basic Proportionality Theorem

In the given figure, DE ∥ AC and DF ∥ AE Prove that BF/FE = BE/EC

TextBasic Proportionality Theorem (Thales Theorem)Converse of Basic Proportionality Theorem

The diagonals of a quadrilateral ABCD intersect each other at the point O such that AO/BO = CO/OD Show that quadrilateral ABCD is a trapezium.

TextBasic Proportionality Theorem (Thales Theorem)Converse of Basic Proportionality Theorem