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If cos (α + β) = 0, then value of cos((α + β)/2) is equal to :
If sin (α + β) = 1, then the value of sin((α + β)/2) is :
If A and B are acute angles such that sin (A – B) = 0 and 2 cos (A + B) – 1 = 0, then find angles A and B.
Assertion (A) : In a right angle triangle ABC, ∠B = 90°. Therefore the value of cos (A + C) is equal to 0. Reason (R) : A + B + C = 180° and cos 90° = 0.
If sin(A + B) = 1 and cos(A − B) = √3/2, 0° < A, B < 90°, find the measure of angles A and B.
Assertion (A): The value of sin 90° = 0. Reason (R): The value of cos 90° = 0
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