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Prove that : tan θ/(1 − cot θ) + cot θ/(1 − tan θ) = 1 + sec θ cosec θ
In a right triangle ABC, right-angled at A, if sin B = 1/4, then the value of sec B is
If x = cos 30° – sin 30° and y = tan 60° – cot 60°, then
The value of (2 tan 60°)/(1 − tan² 60°) is same as the value of
(1 − tan²30°)/(1 + tan²30°) is equal to
sec A = 2 cos A is true for A =
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