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If A₁ denotes the area of region bounded by y² = 4x, x = 1 and x-axis in the first quadrant and A₂ denotes the area of region bounded by y² = 4x, x = 4, find A₁ : A₂.
Find the area of the region bounded by the curve 4x² + y² = 36 using integration.
The area bounded by the curve y = √x, Y-axis and between the lines y = 0, y = 3 is :
The area (in sq. units) of the region bounded by the curve y = x, x-axis, x = 0 and x = 2 is :
Using integration, find the area of the region bounded by the parabola y² = 4ax and its latus rectum.
Using integration, find the area of the region {(x, y) : 4x² + 9y² ≤ 36, 2x + 3y ≥ 6}.
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