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If x = e^(cos 3t) and y = e^(sin 3t), prove that dy/dx = – (y log x)/(x log y).
Show that : d/dx(|x|) = x/|x|, x ≠ 0
Derivative of e²ˣ with respect to eˣ, is:
If xeʸ = 1, then the value of dy/dx at x = 1 is :
Derivative of e^(sin²x) with respect to cos x is :
∫ 2^(x+2) dx is equal to :
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