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Find : ∫ (e⁴ˣ – 1)/(e⁴ˣ + 1) dx
If ∫₋₂³ x² dx = k∫₀² x² dx + ∫₂³ x² dx, then the value of k is :
∫₀^(π/6) sec²(x − π/6) dx is equal to :
If d/dx [f(x)] = ax + b and f(0) = 0, then f(x) is equal to
Anti-derivative of (tan x - 1)/(tan x + 1) with respect to x is
Evaluate ∫_(log√2)^(log√3) 1/((eˣ + e⁻ˣ)(eˣ - e⁻ˣ)) dx
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