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If |a→| = 2 and – 3 ≤ k ≤ 2, then |ka→| ∈ :
If →a + →b = î and →a = 2î − 2ĵ + 2k̂, then |→b| equals :
A unit vector along the vector 4î - 3k̂ is :
The magnitude of the vector 6î − 2ĵ + 3k̂ is
In a parallelogram PQRS, PQ = 3î − 2ĵ + 2k̂ and PS = −î − 2k̂. Find |PR| and |QS|.
If a→ and b→ are unit vectors and θ is the angle between them, then prove that sin(θ/2) = (1/2)|a→ - b→|.
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