If A₁ denotes the area of region bounded by y² = 4x, x = 1 and x-axis in the first quadrant and A₂ denotes the area of region bounded by y² = 4x, x = 4, find A₁ : A₂.
The area bounded by the curve y = √x, Y-axis and between the lines y = 0, y = 3 is :
Using integration, find the area of the region bounded by the curve y = √(4 – x²), the lines x = –√2 and x = √3 and the x-axis.
Using integration, evaluate the area of the region bounded by the curve y = x², the lines y = 1 and y = 3 and the y-axis.
Sketch the region bounded by the lines 2x + y = 8, y = 2, y = 4 and the y-axis. Hence, obtain its area using integration.
Using integration, find the area of the region {(x, y) : 4x² + 9y² ≤ 36, 2x + 3y ≥ 6}.
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