A proton with kinetic energy 1·3384 × 10⁻¹⁴ J moving horizontally from north to south, enters a uniform magnetic field B of 2·0 mT directed eastward. Calculate : (a) the speed of the proton (b) the magnitude of acceleration of the proton (c) the radius of the path traced by the proton [Take (q/m) for proton = 1·0 × 10⁸ C/kg]

Question

TextLorentz Force on a Moving Charge in Magnetic FieldMotion of Charged Particle in Uniform Magnetic FieldCBSE PYQ

Similar Questions

Two charged particles P and Q, having the same charge but different masses mP and mQ, start from rest and travel equal distances in a uniform electric field E in time tP and tQ respectively. Neglecting the effect of gravity, the ratio tP/tQ is :

MCQ (Single)Electric Field and Its DefinitionMotion of Charged Particle in Uniform Magnetic Field

Assertion (A) : An electron and a proton enter with the same momentum p in a magnetic field B such that p ⊥ B. Then both describe a circular path of the same radius. Reason (R) : The radius of the circular path described by the charged particle (charge q, mass m) moving in the magnetic field B is given by r = mv/qB.

Assertion-Reason

Lorentz Force on a Moving Charge in Magnetic Field

Motion of Charged Particle in Uniform Magnetic Field