A stone dropped from a window reaches the ground in 0.5 seconds -
A body is thrown vertically upward with velocity u, the greatest height h to which it will rise is,
How will the equations of motion for an object moving with a uniform velocity change?
Two objects of masses m₁ and m₂ having the same size are dropped simultaneously from heights h₁ and h₂ respectively. Find out the ratio of time they would take in reaching the ground. Will this ratio remain the same if (i) one of the objects is hollow and the other one is solid and (ii) both of them are hollow, size remaining the same in each case. Give reason.
Assertion (A): If the velocity of a body in uniform motion changes, its acceleration cannot remain constant. Reason (R): If a body is thrown vertically upward, the relationship between initial velocity (u) and acceleration (a) at any moment is v² – u² = 2as.
A stone is thrown in a vertically upward direction with a velocity of 5 m s-1. If the acceleration of the stone during its motion is 10 m s–2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?
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