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ABC is an isosceles triangle in which AB = AC. AD bisects exterior angle PAC and CD || AB. Show that (i) ∠ DAC = ∠ BCA and (ii) ABCD is a parallelogram.
In parallelogram ABCD, two points P and Q are taken on diagonal BD such that DP = BQ. Show that: (i) ∆ APD ≅ ∆ CQB (ii) AP = CQ (iii) ∆ AQB ≅ ∆ CPD (iv) AQ = CP (v) APCQ is a parallelogram
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