ABC and BDE are two equilateral triangles such that D is the mid-point of BC. Then ar (BDE) = 1/4 ar (ABC).

Papers Sign In Request access

Free previous-year papers & practice for JEE, NEET and CBSE Boards.

Papers Privacy Terms Contact

Papers Sign In Request access

Free previous-year papers & practice for JEE, NEET and CBSE Boards.

Papers Privacy Terms Contact

Area of Triangle Using Base and Height | PadhAiPro

Question

True/FalseArea of Triangle Using Base and HeightNCERT Exemplar

Page 1 of 1

Similar Questions

PQRS is a square. T and U are respectively, the mid-points of PS and QR (Fig. 9.9). Find the area of ∆ OTS, if PQ = 8 cm, where O is the point of intersection of TU and QS.

TextArea of Triangle Using Base and Height

X and Y are points on the side LN of the triangle LMN such that LX = XY = YN. Through X, a line is drawn parallel to LM to meet MN at Z (See Fig. 9.12). Prove that ar (LZY) = ar (MZYX)

TextArea of Triangle Using Base and Height

ABCD is a square. E and F are respectively the mid-points of BC and CD. If R is the mid-point of EF (Fig. 9.15), prove that ar (AER) = ar (AFR)

TextArea of Triangle Using Base and Height

In Fig. 9.23, BD || CA, E is mid-point of CA and BD = 1/2 CA. Prove that ar (ABC) = 2ar (DBC)

TextArea of Triangle Using Base and Height

In Fig. 9.24, CD || AE and CY || BA. Prove that ar (CBX) = ar (AXY)

TextArea of Triangle Using Base and Height

In Fig. 9.25, ABCDE is any pentagon. BP drawn parallel to AC meets DC produced at P and EQ drawn parallel to AD meets CD produced at Q. Prove that ar (ABCDE) = ar (APQ)

TextArea of Triangle Using Base and Height