If AD and PM are medians of triangles ABC and PQR respectively where △ABC ~ △PQR, prove that AB/PQ = AD/PM
A vertical pole of height 10 m casts a shadow of 15 m on the ground and at the same time, a tower casts a shadow of 45 m on the ground. Find the height of the tower.
In the given figure, QR/QS = QT/PR and ∠1 = ∠2. Prove that △ PQS ~ △ TQR.
It is given that sides AB and AC and median AD of ΔABC are respectively proportional to sides PQ and PR and median PM of another ΔPQR. Show that ΔABC ~ ΔPQR.
If in ∆ABC and ∆DEF, AB/EF = AC/DE then they will be similar when
In the above figure, the criterion of similarity by which △ABC ~ △PQR is :
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