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The rate of a reaction doubles when temperature changes from 27°C to 37°C. Calculate energy of activation for the reaction. (R = 8.314 J K⁻¹ mol⁻¹) (Given: log 2 = 0.3010, log 3 = 0.4771, log 4 = 0.6021)
What happens to the rate constant k and activation energy Ea as the temperature of a chemical reaction is increased ? Justify.
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