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A woman borrowed ₹ 10,00,000 from her friend and promised to return the borrowed money in monthly instalments beginning from the next month. After one month, she returned ₹ 10,000, the next month she returned ₹ 15,000, the third month she returned ₹ 20,000 and so on, thereby increasing the monthly instalment uniformly.
The 20th term of the A.P. : 10√2, 6√2, 2√2,.... is :
22nd term of the A.P. : 3/2, 1/2, -1/2, -3/2, ........ is
Find the A.P. whose third term is 16 and seventh term exceeds the fifth term by 12. Also, find the sum of first 29 terms of the A.P.
Find the sum of first 20 terms of an A.P. whose nth term is given by aₙ = 5 + 2n. Can 52 be a term of this A.P. ?
If the first term of an A.P. is 5, the nth term is 40 and the sum of first n terms is 180, find the value of n.
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