If the point A (2, – 4) is equidistant from P (3, 8) and Q (–10, y), find the values of y. Also find distance PQ.

Question

TextDistance Formula Between Two Points in Coordinate Plane

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AD is a median of △ABC with vertices A(5, −6), B(6, 4) and C(0, 0). Length AD is equal to :

If the distance between the points (3, −5) and (x, −5) is 15 units, then the values of x are :

Distance Formula Between Two Points in Coordinate Plane

The distance of the point A(–3, –4) from x-axis is

Prove that abscissa of a point P which is equidistant from points with coordinates A(7, 1) and B(3, 5) is 2 more than its ordinate.

The distance of point (a, –b) from x-axis is

The distance of point P(3a, 4a) from y-axis is