Calculate the energy released/absorbed in the following nuclear reaction : ¹²₆C + ¹²₆C → ²⁰₁₀Ne + ⁴₂He Given : m(¹²₆C) = 12·000000 u m(²⁰₁₀Ne) = 19·992439 u m(⁴₂He) = 4·002603 u 1 u = 931 MeV/c²

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TextNuclear Binding Energy and Its SignificanceCBSE PYQ

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