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Calculate the emf of the following cell at 298 K : Al (s) | Al³⁺ (0·001 M) || Ni²⁺ (0·1 M) | Ni (s). [Given : E°(Al³⁺/Al) = –1·66 V, E°(Ni²⁺/Ni) = –0·25 V, log 10 = 1]
With the help of a graph explain why it is not possible to determine Λ°m for a weak electrolyte by extrapolating the molar conductivity (Λm) versus C^(1/2) curve as for strong electrolyte.
The molar conductivities of NH₄⁺ and Cl⁻ ion are 73·8 S cm² mol⁻¹ and 76·2 S cm² mol⁻¹ respectively. The conductivity of 0·1 M NH₄Cl is 1·29 × 10⁻² S cm⁻¹. Calculate its molar conductivity and degree of dissociation.
Calculate the half-cell potential at 298 K for the reaction : Zn²⁺ + 2e⁻ → Zn if [Zn²⁺] = 0·1 M and E°(Zn²⁺/Zn) = –0·76 V.
For a galvanic cell, the following half reactions are given. Decide, which will remain as reduction reaction and which will be reversed to become an oxidation reaction. Give reason for your answer. (I) Cr³⁺ + 3e⁻ → Cr(s); E° = – 0·74 V (II) Fe²⁺ + 2e⁻ → Fe(s); E° = – 0·44 V
Represent the cell in which the following reaction takes place : Mg(s) + 2Ag⁺(0·001 M) → Mg²⁺ (0·100 M) + 2Ag(s) Calculate E_cell if E°_cell = 3·17 V. (log 10 = 1)
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