If ∫₀¹ dx / (eˣ + e⁻ˣ) = tan⁻¹ e + k, then the value of k is :

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Second Fundamental Theorem of Integral Calculus, Evaluation of Definite Integrals by Substitution Method | PadhAiPro

Question

MCQ (Single)Second Fundamental Theorem of Integral CalculusEvaluation of Definite Integrals by Substitution Method

Find : ∫ x √(1 + 2x) dx

Evaluate : ∫₀^(π²/4) (sin √x)/√x dx

Evaluation of Definite Integrals by Substitution Method

Evaluate : ∫₀^π (sin x + cos x)/(9 + 16 sin 2x) dx

Evaluate : ∫₀^(π/2) sin 2x tan⁻¹(sin x) dx

∫₀^(π/2) (sin x – cos x)/(1 + sin x cos x) dx is equal to :

The value of ∫₀³ dx/√(9–x²) is: