Question

Calculate the energy released in MeV in the following reaction: ²₁H + ³₁H → ⁴₂He + n Given: m(²₁H) = 2.014102 u m(³₁H) = 3.016049 u m(⁴₂He) = 4.002603 u mₙ = 1.008665 u

In a fission event of ²³⁸₉₂U by fast moving neutrons, no neutrons are emitted and final products, after the beta decay of the primary fragments, are ¹⁴⁰₅₈Ce and ⁹⁹₄₄Ru. Calculate Q for this process. Neglect the masses of electrons/positrons emitted during the intermediate steps.