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Find (x + 1)⁶ + (x – 1)⁶. Hence or otherwise evaluate (√2 + 1)⁶ + (√2 – 1)⁶.
Prove that ∑ᵣ₌₀ⁿ 3ʳ ⁿCᵣ = 4ⁿ.
Find the value of (a² + √(a²–1))⁴ + (a² – √(a²–1))⁴.
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