Loading...
Find the equation of the hyperbola with foci (0, ± 3) and vertices (0, ± √11/2).
Find the equation of the hyperbola where foci are (0, ±12) and the length of the latus rectum is 36.
y2/9 – x2/27 = 1
9y2 – 4x2 = 36
16x2 – 9y2 = 576
5y2 – 9x2 = 36
© 2026 PadhAiPro. This question is provided for educational purposes.