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Calculate the standard enthalpy of formation of CH3OH(l) from the following data: CH3OH (l) + 3/2 O2(g) → CO2(g) + 2H2O(l) ; ∆rH = –726 kJ mol–1 C(graphite) + O2(g) → CO2(g) ; ∆cH = –393 kJ mol–1 H2(g) + 1/2 O2(g) → H2O(l); ∆f H = –286 kJ mol–1.
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