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Two vectors are given as r⃗ =2 î+3ĵ+ 5k̂ and F⃗ =3 î-2ĵ+ 4k̂. Find the resultant vector τ⃗=r⃗XF⃗
Torque τ acting on a particle at position r due to a force F is
If r = (i + 2j) m and F = 3i N, the torque r×F is
A 1 kg particle at r = (i + j) m moves with v = (2i − j) m s−1. Its angular momentum about the origin is
The direction of torque r×F is
Torque τ⃗ acting on a particle at position r⃗ due to a force F⃗ is
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