(a) Explain why the standard molar enthalpy of formation of Cl₂(g) is zero at 298 K, while that of H₂O(g) is not. (b) State the First Law of Thermodynamics and provide its mathematical expression.

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TextEnthalpy of Combustion, Formation and AtomizationFirst Law of Thermodynamics

Similar Questions

The combustion of one mole of benzene takes place at 298 K and 1 atm. After combustion, CO2(g) and H2O (1) are produced and 3267.0 kJ of heat is liberated. Calculate the standard enthalpy of formation, ∆f H of benzene. Standard enthalpies of formation of CO2(g) and H2O(l) are –393.5 kJ mol–1 and – 285.83 kJ mol–1 respectively.

TextEnthalpy of Combustion, Formation and Atomization

The enthalpies of all elements in their standard states are:

MCQ (Single)Enthalpy of Combustion, Formation and Atomization