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What number must be added to each of the numbers 4, 6, 8, 11 in order to get the four numbers in proportion?
Using Componendo and Dividendo solve for x: (√(2x + 2) + √(2x - 1)) / (√(2x + 2) - √(2x - 1)) = 3
If \frac{4x^2 + 3y^2}{4x^2 - 3y^2} = \frac{13}{11}, where x and y are positive, find x : y.
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