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If sec θ − tan θ = m, then the value of sec θ + tan θ is :
If a sec θ + b tan θ = m and b sec θ + a tan θ = n, prove that a² + n² = b² + m²
Use the identity : sin²A + cos²A = 1 to prove that tan²A + 1 = sec²A. Hence, find the value of tan A, when sec A = 5/3, where A is an acute angle.
Prove the following trigonometric identity : (1 + cosec A)/cosec A = cos² A/(1 − sin A)
Let 2A + B and A + 2B be acute angles such that sin(2A + B) = √3/2 and tan(A + 2B) = 1. Find the value of cot(4A − 7B).
Assertion (A) : For an acute angle θ, sec θ = 3 ⇒ tan θ = 2√2 . Reason (R) : sec²θ = 1 − tan²θ for all values of θ.
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