Question

Calculate the emf of the following cell at 25°C: Zn (s) | Zn²⁺ (0.1 M) || H⁺ (0.01 M) | H₂ (g) (1 bar), Pt (s) [Given: E°(Zn²⁺/Zn) = – 0.76 V, E°(H⁺/H₂) = 0.00 V, log 10 = 1]

State Kohlrausch law of independent migration of ions. Why does the conductivity of a solution decrease with dilution?

The resistance and conductivity of a conductivity cell containing 0·001 M KCl solution at 298 K are 1200 Ω and 1·5 × 10⁻⁴ S cm⁻¹. Calculate its cell constant and molar conductivity.

Calculate the emf of the following cell : Zn (s)|Zn²⁺ (0·01 M) || (0·001 M) Ag⁺|Ag (s) Given : E°(Zn²⁺/Zn) = -0·76 V and E°(Ag⁺/Ag) = +0·80 V [log 2 = 0·3010, log 3 = 0·4771, log 10 = 1]