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If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, then prove that the other two sides are divided in the same ratio.
In the adjoining figure, PQ ∥ XY ∥ BC, AP = 2 cm, PX = 1.5 cm and BX = 4 cm. If QY = 0.75 cm, then AQ + CY =
In the adjoining figure, ABCD is a trapezium in which XY ∥ AB ∥ CD. If AX = 2/3 AD, then CY : YB =
E and F are points on the sides AB and AC respectively of a △ABC such that AE/EB = AF/FC = 1/2. Which of the following relation is true ?
The corresponding sides of △ABC and △PQR are in the ratio 3 : 5. AD⊥BC and PS⊥QR as shown in the following figures :
State basic proportionality theorem. Use it to prove the following : If three parallel lines l, m, n are intersected by transversals q and s as shown in the adjoining figure, then AB/BC = DE/EF.
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