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Find : ∫ x √(1 + 2x) dx
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Given d/dx F(x) = 1/√(2x – x²) and F(1) = 0, find F(x).
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If ∫₋₂³ x² dx = k∫₀² x² dx + ∫₂³ x² dx, then the value of k is :
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