Assertion (A): ab + ac + 2b + 2c = (a + 2)(b + c) Reason (R): Grouping the terms in suitable pairs can give a common binomial factor.

Question

Assertion-ReasonFactorisation by Regrouping Terms

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By regrouping, xy + 3x + 2y + 6 factorises as

Factorise by regrouping: 15pq + 15 + 9q + 25p

Factorise: z - 7 + 7xy - xyz

TextFactorisation by Regrouping Terms

Factorise: a^2 + 2ab + b^2 - 16c^2

Factorise: 6xy - 4y + 6 - 9x