Question

Calculate the enthalpy change for the process CCl4(g) → C(g) + 4 Cl(g) and calculate bond enthalpy of C – Cl in CCl4(g). ∆vapH(CCl4) = 30.5 kJ mol–1. ∆fH⊖ (CCl4) = –135.5 kJ mol–1. ∆aH⊖ (C) = 715.0 kJ mol–1, where ∆aH⊖ is enthalpy of atomisation ∆aH⊖ (Cl2) = 242 kJ mol–1