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Prove that : tan θ/(1 − cot θ) + cot θ/(1 − tan θ) = 1 + sec θ cosec θ
In a right triangle ABC, right-angled at A, if sin B = 1/4, then the value of sec B is
Assertion (A) : For an acute angle θ, value of cosec θ cannot be 1/√2. Reason (R) : cosec θ ≥ 1 for 0° ≤ θ ≤ 90°
Prove the following trigonometric identity : (1 + cosec A)/cosec A = cos²A/(1 − sin A)
sec A = 2 cos A is true for A =
Prove that (cos A + sin A – 1)/(cos A – sin A + 1) = cosec A – cot A
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