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If sec θ − tan θ = m, then the value of sec θ + tan θ is :
Prove that : tan θ/(1 − cot θ) + cot θ/(1 − tan θ) = 1 + sec θ cosec θ
In a right triangle ABC, right-angled at A, if sin B = 1/4, then the value of sec B is
If a sec θ + b tan θ = m and b sec θ + a tan θ = n, prove that a² + n² = b² + m²
Use the identity : sin²A + cos²A = 1 to prove that tan²A + 1 = sec²A. Hence, find the value of tan A, when sec A = 5/3, where A is an acute angle.
Assertion (A) : For an acute angle θ, sec θ = 3 ⇒ tan θ = 2√2 . Reason (R) : sec²θ = 1 − tan²θ for all values of θ.
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