Question

The distance of the point A(–3, –4) from x-axis is

Prove that abscissa of a point P which is equidistant from points with coordinates A(7, 1) and B(3, 5) is 2 more than its ordinate.

The distance of point (a, –b) from x-axis is

If x = cos 30° – sin 30° and y = tan 60° – cot 60°, then