Calculate the e.m.f. of the following cell at 298K : Fe(s) | Fe²⁺ (0.001 M) || H⁺ (0.01M) | H₂(g) (1 bar) | Pt(s) Given that E°cell = +0.44 V [log 2 = 0.3010 log 3 = 0.4771 log 10 = 1]

EMF of a Cell and Its Calculation, Nernst Equation for Cell Potential | PadhAiPro

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TextEMF of a Cell and Its CalculationNernst Equation for Cell PotentialCBSE PYQ

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