Loading...
Calculate the emf of the following cell at 25°C: Zn (s) | Zn²⁺ (0.1 M) || H⁺ (0.01 M) | H₂ (g) (1 bar), Pt (s) [Given: E°(Zn²⁺/Zn) = – 0.76 V, E°(H⁺/H₂) = 0.00 V, log 10 = 1]
State Kohlrausch law of independent migration of ions. Why does the conductivity of a solution decrease with dilution?
What should be the signs (positive/negative) for E°Cell and ΔG° for a spontaneous redox reaction occurring under standard conditions ?
State Faraday's first law of electrolysis.
Calculate the emf of the following cell at 298 K : Fe(s) | Fe²⁺ (0.01M) || H⁺(1M) | H₂(g) (1 bar), Pt(s). Given E°Cell = 0.44 V.
Calculate the emf of the following cell : Zn (s)|Zn²⁺ (0·01 M) || (0·001 M) Ag⁺|Ag (s) Given : E°(Zn²⁺/Zn) = -0·76 V and E°(Ag⁺/Ag) = +0·80 V [log 2 = 0·3010, log 3 = 0·4771, log 10 = 1]
© 2026 PadhAiPro. This question is provided for educational purposes.