Calculate the emf of the following cell at 298 K : Fe(s) | Fe²⁺ (0.01M) || H⁺(1M) | H₂(g) (1 bar), Pt(s). Given E°Cell = 0.44 V.

Question

TextNernst Equation for Cell PotentialRelation Between Gibbs Energy and EMF of CellFaraday's First Law of ElectrolysisCBSE PYQ

Similar Questions

Calculate the e.m.f. of the following cell at 298K : Fe(s) | Fe²⁺ (0.001 M) || H⁺ (0.01M) | H₂(g) (1 bar) | Pt(s) Given that E°cell = +0.44 V [log 2 = 0.3010 log 3 = 0.4771 log 10 = 1]

TextEMF of a Cell and Its CalculationNernst Equation for Cell Potential

Calculate the emf of the following cell at 25°C: Zn (s) | Zn²⁺ (0.1 M) || H⁺ (0.01 M) | H₂ (g) (1 bar), Pt (s) [Given: E°(Zn²⁺/Zn) = – 0.76 V, E°(H⁺/H₂) = 0.00 V, log 10 = 1]

Text