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The unit vector perpendicular to both vectors î + k̂ and î – k̂ is :
Assertion (A) : For two non-zero vectors a→ and b→, a→ · b→ = b→ · a→. Reason (R) : For two non-zero vectors a→ and b→, a→ × b→ = b→ × a→.
Let a→ and b→ be two non-zero vectors. Prove that |a→ × b→| ≤ |a→||b→|. State the condition under which equality holds, i.e., |a→ × b→| = |a→||b→|.
Let →a be any vector such that |→a| = a. The value of |→a × î|² + |→a × ĵ|² + |→a × k̂|² is:
Find a vector of magnitude 4 units perpendicular to each of the vectors 2î − ĵ + k̂ and î + ĵ − k̂ and hence verify your answer.
Given a⃗ = 2î - ĵ + k̂, b⃗ = 3î - k̂ and c⃗ = 2î + ĵ - 2k̂. Find a vector d⃗ which is perpendicular to both a⃗ and b⃗ and c⃗ · d⃗ = 3.
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