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Let θ be the angle between two unit vectors â and b̂ such that sin θ = 3/5. Then, â . b̂ is equal to :
In the given figure, ABCD is a parallelogram. If AB⃗ = 2î – 4ĵ + 5k̂ and DB⃗ = 3î – 6ĵ + 2k̂, then find AD⃗ and hence find the area of parallelogram ABCD.
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