Question

Find the equation of the line passing through the point of intersection of the lines x/1 = (y – 1)/2 = (z – 2)/3 and (x – 1)/0 = y/(– 3) = (z – 7)/2 and perpendicular to these given lines.

Two vertices of the parallelogram ABCD are given as A(– 1, 2, 1) and B(1, – 2, 5). If the equation of the line passing through C and D is (x – 4)/1 = (y + 7)/(– 2) = (z – 8)/2, then find the distance between sides AB and CD. Hence, find the area of parallelogram ABCD.

The angle which the line x/1 = y/−1 = z/0 makes with the positive direction of Y-axis is :

The Cartesian equation of the line passing through the point (1, −3, 2) and parallel to the line r⃗ = (2 + λ)î + λĵ + (2λ − 1)k̂ is :