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Direction ratios of a vector parallel to line (x–1)/2 = – y = (2z+1)/6 are :
The lines (1–x)/2 = (y–1)/3 = z/1 and (2x–3)/2p = y/(–1) = (z–4)/7 are perpendicular to each other for p equal to:
The angle which the line x/1 = y/−1 = z/0 makes with the positive direction of Y-axis is :
The Cartesian equation of the line passing through the point (1, −3, 2) and parallel to the line r⃗ = (2 + λ)î + λĵ + (2λ − 1)k̂ is :
Find the co-ordinates of the foot of the perpendicular drawn from the point (2, 3, −8) to the line (4 − x)/2 = y/6 = (1 − z)/3. Also, find the perpendicular distance of the given point from the line.
Find the shortest distance between the lines L₁ & L₂ given below : L₁ : The line passing through (2, -1, 1) and parallel to x/1 = y/1 = z/3, and L₂ : r⃗ = î + (2μ + 1)ĵ - (μ + 2)k̂.
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