Loading...
Derive graphically the equation for position-time relation for an object travelling a distance 's' in time 't' under uniform acceleration.
A stone dropped from a window reaches the ground in 0.5 seconds -
Imagine a rocket named Vayu-1 that is designed for a space mission. The rocket has a mass of 5,000 kg and is launched from the Earth's surface. The rocket engine produces a constant thrust of 60,000 N. The rocket accelerates vertically upward through the atmosphere. During the ascent, the rocket's engines provide thrust for the first 30 seconds. After that, the rocket continues its motion with a constant velocity due to the thrust being cut off.
Define kinetic energy and provide its formula.
A cyclist travels along a straight path with a constant acceleration of 2 m/s². If the cyclist's initial velocity is 5 m/s, what is the cyclist's velocity after 4 seconds? Also, calculate the total distance covered in this time.
With the help of Second Law of Motion and the Universal Law of Gravitation derive an expression for acceleration due to gravity 'g'.
© 2026 PadhAiPro. This question is provided for educational purposes.
